(6x-4)(x+2)=2(11x-19)+2(3x^2-13)

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Solution for (6x-4)(x+2)=2(11x-19)+2(3x^2-13) equation: 



(6x-4)(x+2)=2(11x-19)+2(3x^2-13)

We move all terms to the left:

(6x-4)(x+2)-(2(11x-19)+2(3x^2-13))=0

We multiply parentheses ..

(+6x^2+12x-4x-8)-(2(11x-19)+2(3x^2-13))=0



We calculate terms in parentheses: -(2(11x-19)+2(3x^2-13)), so:

2(11x-19)+2(3x^2-13)

We multiply parentheses

6x^2+22x-38-26

We add all the numbers together, and all the variables

6x^2+22x-64

Back to the equation:

-(6x^2+22x-64)



We get rid of parentheses

6x^2-6x^2+12x-4x-22x-8+64=0

We add all the numbers together, and all the variables

-14x+56=0

We move all terms containing x to the left, all other terms to the right

-14x=-56

x=-56/-14

x=+4

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